Choose exam board for KS4 Computer Science (GCSE)
Choose exam board for KS4 English
Choose exam board for KS4 French
Choose exam board for KS4 Geography
Choose exam board for KS4 German
Choose exam board for KS4 History
Choose tier for KS4 Maths
Choose exam board for KS4 Music
Choose exam board for KS4 Physical education (GCSE)
Choose exam board for KS4 Religious education (GCSE)
Choose exam board for KS4 Spanish

Lesson details

Learning outcome

I can derive and use the formula for the sine rule.

Key learning points

  1. The sides of a triangle are proportional to the sines of their opposite angles
  2. A diagram can aid with understanding this
  3. The sine rule is useful when you know an angle and side pair and wish to find another pair
  4. In order to do this, you will need either a side length or an angle

Keywords

  • Sine rule - The sine rule is a formula used for calculating either an unknown side length or the size of an unknown angle.

Common misconception

Pupils may be uncertain about which angle pairs with which side.

The angle is paired with the side length that is opposite.

Teacher tip

You may wish to display the sine rule along with an appropriate diagram on a separate board so that pupils can reference this throughout the lesson.

Licence

This content is © Oak National Academy Limited (2025), licensed on Open Government Licence version 3.0
except where otherwise stated. See Oak's terms & conditions
(Collection 2).

Lesson video

Loading...

Prior knowledge starter quiz

6 Questions

Q1.
Which of the following are equivalent to $$\sin(\theta°)=\frac{\text{opp}}{\text{hyp}}$$?

Correct answer: $$\text{hyp}\times\sin(\theta°)=\text{opp}$$
Correct answer: $$\theta°=\arcsin\left(\frac{\text{opp}}{\text{hyp}}\right)$$
Correct answer: $$\text{hyp}=\frac{\text{opp}}{\sin(\theta°)}$$
$$\text{hyp}=\frac{\sin(\theta°)}{\text{opp}}$$

Q2.
Using $$\sin(A)=\frac{p}{c}$$, identify all the rearrangements.

An image in a quiz
Correct answer: $$p = \sin(A) \times c$$
Correct answer: $$c=\frac{p}{\sin(A)}$$
$$p=\frac{c}{\sin(A)}$$
$$c=\frac{\sin(A)}{p}$$

Q3.
Using $$\sin(C)=\frac{p}{a}$$, identify all the rearrangements.

An image in a quiz
$$p=\frac{a}{\sin(C)}$$
Correct answer: $$a=\frac{p}{\sin(C)}$$
Correct answer: $$p = \sin(C) \times a$$
$$a=\frac{\sin(C)}{p}$$

Q4.
An isosceles triangle has lengths 10 cm, 10 cm and 16 cm. The area of the isosceles triangle is cm$$^2$$.

Correct Answer: 48

Q5.
An equilateral triangle has lengths of 10 cm. The area of the triangle, to 1 decimal place, is cm$$^2$$.

Correct Answer: 43.3

Q6.
A regular hexagon has lengths of 6 cm. The area of the hexagon, to the nearest integer, is cm$$^2$$.

Correct Answer: 94

6 Questions

Q1.
When do we use the sine sule?

Correct answer: For calculating either an unknown side length or the size of an unknown angle
For calculating the area of a triangle
For calculating the area of a circle
For ensuring we write signs properly

Q2.
Identify the correct ways to express $$p$$ using the diagram.

An image in a quiz
Correct answer: $$p = \sin(A) \times c$$
Correct answer: $$p = \sin(C) \times a$$
$$p=\frac{a}{\sin(C)}$$
$$p=\frac{c}{\sin(A)}$$

Q3.
Which of the following are correct versions of the sine rule?

Correct answer: $$\frac{a}{\sin(A)}=\frac{b}{\sin(B)}=\frac{c}{\sin(C)}$$
Correct answer: $$\frac{a}{\sin(A)}=\frac{b}{\sin(B)}$$
Correct answer: $$\frac{a}{\sin(A)}=\frac{c}{\sin(C)}$$
Correct answer: $$\frac{b}{\sin(b)}=\frac{c}{\sin(C)}$$
$$\frac{a}{\sin(b)}=\frac{b}{\sin(C)}$$

Q4.
Length $$a$$ is opposite angle A. Work out the size of length $$a$$ giving your answer to 2 decimal places.

An image in a quiz
Correct Answer: 9.74 cm, 9.74

Q5.
Length $$b$$ is opposite angle B. Work out the size of length $$b$$ giving your answer to 2 decimal places.

An image in a quiz
Correct Answer: 13.1 cm, 13.1

Q6.
Work out the size of angle $$\alpha$$ giving your answer to 1 decimal place.

An image in a quiz
Correct Answer: 57.0, 57.0 degrees, 57.0°

To help you plan your 11 maths lesson on: The sine rule, download all teaching resources for free and adapt to suit your pupils' needs...