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      Solve problems using divisibility rules for divisors of 3, 6 and 9

      Lesson details

      Learning outcome

      I can solve problems using divisibility rules for divisors of 3 and 6

      Key learning points

      1. For a number to be divisible by three, the dgit sum of the number must be a divisible by 3
      2. For a number to be divisible by 6, it must be divisible by both 2 and 3
      3. If you halve a number and the digit sum of the half is a multiple of 3 then the number is divisible by 6

      Keywords

      • Digit sum - The sum of the digits that comprise a number.

      • Divisible / divisibility - Divisibility is when division of a number results in another whole number. A number is divisible by another if it can be shared exactly with no remainder.

      • Multiple - A multiple is the result of multiplying a number by another whole number.

      Common misconception

      Pupils may find it difficult to solve problems or misunderstand questions.

      Model clearly how to identify key phrases and words which will identify the operation and equation required for word problems. This could involve drawing bar models or other representations.

      Teacher tip

      By this point fluency in 3, 6 and 9 times tables will support children in solving these problems. Continue to chorally rehearse the 3 and 6 times tables.

      Licence

      This content is © Oak National Academy Limited (2025), licensed on Open Government Licence version 3.0
      except where otherwise stated. See Oak's terms & conditions
      (Collection 2).

      Lesson video

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      Prior knowledge starter quiz

      6 Questions

      Q1.
      Which numbers are a multiple of 9?

      48
      Correct answer: 54
      57
      64
      Correct answer: 72

      Q2.
      Identify the multiples of 6

      Correct answer: 72
      Correct answer: 66
      59
      Correct answer: 54
      106

      Q3.
      Match the groups of 30 to the groups of 90 with the same value.

      Correct Answer:6 groups of 30,2 × 90

      2 × 90

      Correct Answer:9 × 30,3 groups of 90

      3 groups of 90

      Correct Answer:30 groups of 12,4 × 90

      4 × 90

      Correct Answer:30 × 15,5 groups of 90

      5 groups of 90

      Q4.
      Look at the word problem, which words suggest we must multiply? Andeep has 4 packs of 3 guinea cards. How many packs does he have altogether?

      altogether
      packs
      Correct answer: of
      how many

      Q5.
      A party needs 909 balloons to decorate a stage. If balloons come in packs of 9, how many packs will be needed? packs

      Correct Answer: 101

      Q6.
      A baker baked 45 pastries and cakes altogether. He can put them in 5 boxes of 9 If he puts them into boxes of 3, how many boxes will he need? boxes.

      Correct Answer: 15

      6 Questions

      Q1.
      All multiples of 9 are also multiples of

      Correct Answer: 3, three

      Q2.
      Select the multiples of 3 and 6

      Correct answer: 18
      23
      45
      Correct answer: 48
      Correct answer: 60

      Q3.
      The digit sum of 855 is 18. It __________

      Correct answer: is divisible by 9
      is not divisible by 9

      Q4.
      Select the numbers that are divisible by 9:

      Correct answer: 81
      273
      Correct answer: 6,543
      815
      Correct answer: 4,545

      Q5.
      A baker has 966 cakes, select the boxes below to show which boxes he’ll be able to split all cupcakes into equally.

      Correct answer: 3
      Correct answer: 6
      9

      Q6.
      A sweet factory has made 453 lollipops, select the boxes below to show which boxes he’ll be able to split all cupcakes into equally.

      Correct answer: 3
      6
      9

      To help you plan your 4 maths lesson on: Solve problems using divisibility rules for divisors of 3, 6 and 9, download all teaching resources for free and adapt to suit your pupils' needs...