Myths about teaching can hold you back
- Year 7
Simplifying fractions
I can simplify fractions by dividing both the numerator and denominator by common factors and know why this works.
- Year 7
Simplifying fractions
I can simplify fractions by dividing both the numerator and denominator by common factors and know why this works.
These resources were made for remote use during the pandemic, not classroom teaching.
Switch to our new teaching resources now - designed by teachers and leading subject experts, and tested in classrooms.
Lesson details
Key learning points
- When a fraction is multiplied by 1 it remains the same but may look different.
- Simplifying fractions can be shown to be the inverse of multiplying to find equivalent fractions.
- A fraction can be written more simply but remain equivalent by dividing the numerator and denominator by a common factor
- A fraction can be written in simplest form by dividing the numerator.
Keywords
Factor - A factor is a term which exactly divides another term.
Highest common factor - The highest common factor is the common factor which can be divided by all other possible common factors.
Product of primes - Expressing a number as a product of primes means writing it uniquely as a product of its factors that are prime numbers.
Common misconception
Pupils may think they just 'get rid' of integers which appear in both numerator and denominator.
Reinforce that you are multiplying by 1, which doesn't change the value and therefore can be omitted from further calculations.
To help you plan your year 7 maths lesson on: Simplifying fractions, download all teaching resources for free and adapt to suit your pupils' needs...
To help you plan your year 7 maths lesson on: Simplifying fractions, download all teaching resources for free and adapt to suit your pupils' needs.
The starter quiz will activate and check your pupils' prior knowledge, with versions available both with and without answers in PDF format.
We use learning cycles to break down learning into key concepts or ideas linked to the learning outcome. Each learning cycle features explanations with checks for understanding and practice tasks with feedback. All of this is found in our slide decks, ready for you to download and edit. The practice tasks are also available as printable worksheets and some lessons have additional materials with extra material you might need for teaching the lesson.
The assessment exit quiz will test your pupils' understanding of the key learning points.
Our video is a tool for planning, showing how other teachers might teach the lesson, offering helpful tips, modelled explanations and inspiration for your own delivery in the classroom. Plus, you can set it as homework or revision for pupils and keep their learning on track by sharing an online pupil version of this lesson.
Explore more key stage 3 maths lessons from the Comparing and ordering fractions and decimals (positive and negative) unit, dive into the full secondary maths curriculum, or learn more about lesson planning.
Equipment
Licence
Prior knowledge starter quiz
6 Questions
Q1.What word should go in the blank spaces to complete the following statement? Terminating __________ have a finite number of __________ places.
Q2.Write $$0.825$$ as a simplified fraction.
Q3.The fraction which is halfway between 0.2 and 0.9 is $$\square \over 20$$. What number should be written in the square?
Q4.Which of the following are equivalent to $$5.555$$ ?
Q5.Match each decimal to a fraction with the denominator in exponential form.
$$0.00067$$ -
$$\frac{67}{10^5}$$
$$6.7$$ -
$$\frac{67}{10^1}$$
$$0.067$$ -
$$\frac{67}{10^3}$$
$$0.67$$ -
$$\frac{67}{10^2}$$
Q6.Sofia writes $$12.34 = \frac {1234}{10^ \square}$$. What number should she write in the box to make her statement true?
Assessment exit quiz
6 Questions
Q1.Complete the statement. A is a term which exactly divides another term.
Q2.Select all the fractions that simplify to $$2 \over 3$$.
Q3.Which of the following factors of 24 and 90 is the best choice to efficiently simplify $$24\over90$$?
Q4.Write 180 as a product of prime factors.
Q5.Which of these fractions is equivalent to $$360 \over 700$$
Q6.Match each fraction to its simplified equivalent fraction. Use the fact that $$120 = 2^3 \times 3 \times 5$$; $$84 = 2^2 \times 3 \times 7$$ and $$210 = 2 \times 3 \times 5 \times 7$$
$$84\over210$$ -
$$2\over5$$
$$84\over120$$ -
$$7\over10$$
$$120\over210$$ -
$$4\over7$$
$$120\over84$$ -
$$1 \frac{3}{7}$$