Abstract inverse proportion
I can identify, write and solve inverse proportion questions involving algebra.
Abstract inverse proportion
I can identify, write and solve inverse proportion questions involving algebra.
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Lesson details
Key learning points
- Inverse proportion equations are of the form y = k ÷ x^n
- k is the constant of proportionality.
- To find k, you can use a pair of values.
Keywords
Inversely proportional - Two variables are inversely proportional if there is a constant multiplicative relationship between one variable and the reciprocal of the other.
Common misconception
For all direct and inverse proportions, the multiplicative relationship is with x and y.
The multiplicative relationship whether direct or inverse can be shown as y and x^n. Show a ratio table of y and 1/x^2 and a table of y and 1/x. The inverse multiplicative relationship is seen with y and 1/x^2 and not with 1/x.
To help you plan your year 11 maths lesson on: Abstract inverse proportion, download all teaching resources for free and adapt to suit your pupils' needs...
To help you plan your year 11 maths lesson on: Abstract inverse proportion, download all teaching resources for free and adapt to suit your pupils' needs.
The starter quiz will activate and check your pupils' prior knowledge, with versions available both with and without answers in PDF format.
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The assessment exit quiz will test your pupils' understanding of the key learning points.
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Explore more key stage 4 maths lessons from the Direct and inverse proportion unit, dive into the full secondary maths curriculum, or learn more about lesson planning.
Licence
Lesson video
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Starter quiz
6 Questions
3 -
$$\frac{1}{3}$$
5 -
$$\frac{1}{5}$$
$$\frac{3}{2}$$ -
$$\frac{2}{3}$$
2 -
$$\frac{1}{2}$$
12 -
$$\frac{1}{12}$$
$$\frac{5}{9}$$ -
$$\frac{9}{5}$$
Exit quiz
6 Questions
$$y\propto\frac{1}{x^2}$$ -
$$y=\frac{3}{x^2}$$
$$y\propto\frac{1}{\sqrt{x}}$$ -
$$y=\frac{10}{\sqrt{x}}$$
$$y\propto\frac{1}{\sqrt[3]{x}}$$ -
$$y=\frac{3}{4\sqrt[3]{x}}$$
$$y\propto\frac{1}{x}$$ -
$$y=\frac{\sqrt{2}}{x}$$
$$y\propto x^2$$ -
$$y= 9x^2$$
$$y\propto \sqrt{x}$$ -
$$y= 5\sqrt{x}$$
A -
20
B -
1000
C -
62.5