New
New
Year 10
AQA
Foundation

Interpreting I–V graphs

I can take readings from I–V graphs and use these to describe the changing resistance of a component.

New
New
Year 10
AQA
Foundation

Interpreting I–V graphs

I can take readings from I–V graphs and use these to describe the changing resistance of a component.

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Lesson details

Key learning points

  1. In forward–bias, a diode has a very small resistance when the p.d. is larger than the threshold voltage.
  2. In reverse–bias, a diode has a very large resistance and very little current can flow.
  3. The greater the p.d. across a component, the larger the push on electric charges in the component.
  4. The resistance of a component is calculated from an I–V graph using pairs of readings and the equation R = V ÷ I.
  5. The greater the current through a component, the larger the heating effect on it.

Keywords

  • Reverse–bias - When a diode is reverse–biased, it prevents current from flowing.

  • Forward–bias - When a diode is forward–biased, it allows current to flow.

  • Threshold p.d. - The threshold p.d. is the potential difference at which a diode allows current to flow.

  • Fuse - A fuse is a component that has a wire that melts if the current is too high.

  • Ion lattice - In a solid metal, the regular and repeating pattern that metal ions are arranged in is known as an ion lattice.

Common misconception

Pupils often cannot apply the main I–V graphs to similar components.

Describe how the p.d. and current in components behaves to draw out similarities that can be used to describe unfamiliar components.

Use exam questions to provide pupils with further practice in describing or explaining I–V graphs in a range of contexts.
Teacher tip

Licence

This content is © Oak National Academy Limited (2024), licensed on Open Government Licence version 3.0 except where otherwise stated. See Oak's terms & conditions (Collection 2).

Lesson video

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6 Questions

Q1.
What is the function of a diode?
to provide a constant resistance to current
to provide a push to electrons
to increase the flow of current
Correct answer: to allow current to flow in only one direction
Q2.
What does it mean when a diode is in reverse bias?
the diode will make the current flow backwards
the diode is connected to a switch that has been turned off
Correct answer: the p.d. across the diode is the wrong way round for current to flow
the p.d. across the diode is the right way round for current to flow
Q3.
Which of these has a symmetrical I-V graph for both positive and negative p.d.?
Correct answer: filament lamp
LED
diode
Correct answer: resistor
Q4.
Which of the following correctly describes how a fuse wire works?
it prevents current flowing backwards
it allows less current than expected to flow as the p.d. is increased
Correct answer: it heats up and melts when too much current flows
it emits light when a current flows
Q5.
What is the resistance of a diode if it allows 0.16 A to flow when the p.d. across it is 0.8 V?
0.2 Ω
0.96 Ω
1.28 Ω
Correct answer: 5.0 Ω
Q6.
How does this component work?
An image in a quiz
the resistance varies depending on temperature
the resistance varies depending on light level
the resistance varies depending on the direction of the applied p.d.
Correct answer: the resistance varies depending on the way the experimenter turns a dial

6 Questions

Q1.
The characteristics of which component are shown by this I-V graph?
An image in a quiz
Correct answer: a diode
a filament lamp
a fuse
a resistor
Q2.
The characteristics of a diode are shown by this I-V graph. What is its threshold voltage?
An image in a quiz
0.0 V
Correct answer: 0.6 V
0.7 V
1.02 V
Q3.
Which component has a current that increases as the p.d. across it increases, but at higher p.d.s the current does not increase as much as expected?
a diode
Correct answer: a filament lamp
a resistor
a buzzer
Q4.
Which component has an I-V graph that shows the current is directly proportional to the p.d. across it?
a diode
a light emitting diode
a filament lamp
Correct answer: a resistor
Q5.
What is the most appropriate fuse rating for a device that normally uses a current of 9 A?
3 A
5 A
Correct answer: 13 A
Q6.
What happens inside a metal wire with a bigger current through it?
Correct answer: free electrons move more quickly
free electrons do not move more quickly
Correct answer: metal ions vibrate more vigorously
metal ions do not vibrate more vigorously