New
New
Year 4

Use knowledge of division equations and remainders to solve problems

I can use knowledge of division equations and remainders to solve problems.

New
New
Year 4

Use knowledge of division equations and remainders to solve problems

I can use knowledge of division equations and remainders to solve problems.

Lesson details

Key learning points

  1. If the dividend is a multiple of the divisor, there will be no remainder.
  2. If the remainder is greater than the divisor, another equal group can be made.
  3. If the remainder is known, the possibilities for a missing divisor can be found.
  4. If the divisor is known, the possibilities for a missing remainder can be found.
  5. This knowledge can help when solving missing number equations.

Keywords

  • Dividend - The dividend is the whole amount to be divided into groups or divided into equal parts. It is what we are dividing.

  • Divisor - The divisor is the number in each group or the number of equal parts that the whole is divided into or between. It is what we are dividing by.

  • Remainder - A remainder is the amount left over after division when the dividend does not divide exactly by the divisor.

Common misconception

Children may either choose to use a multiple higher than the dividend, e.g. 53 ÷ 9 = , or choose a multiple that is too low, e.g. 57 ÷ 8 = , which results in a remainder greater than the divisor.

When solving equations, refer back to the largest multiple that is less than or equal to the dividend and use number lines to allow children to visualise this.

To deepen understanding further, ask children to make their own sequences of division equations, first keeping the dividend the same and changing the divisor, and then keeping the divisor the same and changing the dividend. Continue to develop number sense, asking them to predict and explain.
Teacher tip

Licence

This content is © Oak National Academy Limited (2024), licensed on Open Government Licence version 3.0 except where otherwise stated. See Oak's terms & conditions (Collection 2).

Lesson video

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6 Questions

Q1.
Complete the sentence. If the dividend in a calculation is not a multiple of the divisor,
Correct answer: there will be a remainder.
there will not be a remainder.
Q2.
Which of the following will not have a remainder?
56 ÷ 9
Correct answer: 56 ÷ 8
Correct answer: 56 ÷ 7
56 ÷ 6
Q3.
Which of these numbers will have a remainder when the divisor is 8?
Correct answer: 36
48
Correct answer: 43
Correct answer: 78
72
Q4.
58 books are sorted onto 9 shelves in the classroom. Are there any books left over?
Correct answer: Yes, because 58 is not a multiple of 9
No, there are no books left over
Q5.
We know that multiples of 6 are even and have a digit sum that is divisible by 3 Which of these numbers will have a remainder when divided by 6?
Correct answer: 51
72
Correct answer: 77
84
Correct answer: 92
Q6.
We know that multiples of 4 must be even and, if halved, will reach an even number. Which of these numbers will have a remainder when divided by 4?
84
Correct answer: 95
Correct answer: 94
96

6 Questions

Q1.
Pencils are put into pots of 7 Which of the total number of pencils won’t divide equally into pots of 7?
28
Correct answer: 32
35
Correct answer: 38
42
Q2.
When dividing 21 into equal groups, which group size will give a remainder?
groups of 3
Correct answer: groups of 4
Correct answer: groups of 5
Correct answer: groups of 6
groups of 7
Q3.
Which of these equations is incorrect?
57 ÷ 8 = 7 r 1
Correct answer: 57 ÷ 6 = 8 r 9
57 ÷ 9 = 6 r 3
Q4.
Jun has fewer that 40 counters. When divided into groups of 7 there are no remainders and when divided into groups of 5 there are no remainders. How many counters must Jun have?
Correct Answer: 35, thirty-five
Q5.
Look at the image.
An image in a quiz
2
3
Correct answer: 4
Correct answer: 5
Correct answer: 6
Q6.
Look at the image.
An image in a quiz
Correct Answer: 33, thirty-three