I can solve a linear equation requiring a single multiplicative step.
I can solve a linear equation requiring a single multiplicative step.
Reciprocal - The reciprocal is the multiplicative inverse of any non-zero number.
When solving equations pupils may not use the inverse operation.
Working out should include each step then pupils can check each step using substitution.
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$$1\over 5$$ - $$5$$
$$−{1\over 5}$$ - $$-5$$
$$4\over 5$$ - $$5\over 4$$
$$−{4\over 5}$$ - $$−{5\over 4}$$
$$5$$ - $${1\over 5}$$
$$−5$$ - $$−{1\over 5}$$
$$\times {2\over 7}$$ - $$\div {7\over 2}$$
$$\div (-{2\over 7})$$ - $$\times( −{7\over 2})$$
$$\times (−7)$$ - $$\div( −{1\over 7})$$
$$\times( −{1\over 7})$$ - $$\div( −7)$$
$$\times {1\over 7}$$ - $$\div 7$$
$$\div {1\over 7}$$ - $$\times 7$$
